In front of you are 3 chests:
Chest A has been labelled with “100 gold coins”,
Chest B has been labelled with “50 gold and 50 silver coins”,
Chest C has been labelled with “100 silver coins”.
You are told that all of the labels are incorrectly placed, as they describe the contents of another chest. To help you determine which is the chest which contains “100 gold coins”, you are allowed to randomly pick a coin from any chest,
Which chest should you pick a coin from?
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From 50 gold and 50 silver. Since this is either 100 gold and 100 sikver. If gold comes up this is the box.
If sikver comes up, then gold is in one of tow other boxes. It is definitely in box labeled silver.
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chest B
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How?
There is no box labelled silver 
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When I say gold I mean 100 gold coins
When I say sikver I mean 100 silver coin
I still see a glitch. Will get back to this.
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See here is the thing:
It says "each chest is wrongly labelled"
So chest 'A' is out of question.
Now that leaves chest 'B' and 'C'.
I would pick it from chest 'B'
Why? Cuz if its a silver coin, it means chest 'C' has 100 gold. and if its a gold coin then chest 'B' itself has 100 gold since we know its currently wrongly labelled so it cannot have 50 gold & 50 silver.
Should i take a bow? :)
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From 50 gold and 50 silver. Since this is either 100 gold and 100 sikver. If gold comes up this is the box.
If sikver comes up, then gold is in one of tow other boxes. It is definitely in box labeled silver.
What I have stated is correct. But if you must get technical, choose from chest B which is labeled 50 silver and 50 gold. If gold comes up this is the box. If sikver comes up, then 100 gold is in chest a or chest c. Chest C is labeled 100 silver. It could be 50 sikver 50 gold or 100 gold. Chest a is leveled 100 gold. It could be 50 silver 50 gold or 100 silver. But 100 silver is taken. So chest a is 50 silver 50 gold. Chest c is 100 gold.
The answer I gave initially stands.
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To the misfortune of the person who identified 100 gold, Gold is down 40 pct from peak.
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^ You're wrong SID_NY. If you pick a coin and it happens to be the one with 100G there will no longer be 100 coins in the chest! :p
I would pick B too.
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Hmm.
Each chest is wrongly labelled;
Chest A has been labelled with "100 gold coins",
Chest B has been labelled with "50 gold and 50 silver coins",
Chest C has been labelled with "100 silver coins".
If I pick from box B, you know it's not 50 silver/gold as it's wrongly labelled. So therefore if I pick a coin from B and it's gold, that means chest B has 100 gold coins, C has 50/50 and A has silver. Another way, I pick a coin from chest B and it's a silver coin, that means gold is chest C, B is silver and A is 50/50.
So therefore 100 gold coins are either in box B or C depending on what coin you pick from B.
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Ok, that's right. Its B.
Next one:
Suppose you are travelling in a train. There are only 4 other people in your berth. They are named 1, 2, 3 and 4 . Your wallet is stolen. Assume that the wallet was stolen by one of these 4 people and that only 3 of them lie.
Here are their statements:
- 1: 2 stole the wallet.
- 2: 3 didn't steal.
- 3: I didn't steal.
- 4: 3 stole your wallet.
Who actually stole your wallet?
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Ok, that's right. Its B.
Next one:
Suppose you are travelling in a train. There are only 4 other people in your berth. They are named 1, 2, 3 and 4 . Your wallet is stolen. Assume that the wallet was stolen by one of these 4 people and that only 3 of them lie.
Here are their statements: - 1: 2 stole the wallet. - 2: 3 didn't steal. - 3: I didn't steal. - 4: 3 stole your wallet.
Who actually stole your wallet?
4 tells the truth .. *3 stole the wallet *
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wrong reasoning but right answer.
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I like this thread.
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wrong reasoning but right answer.
Explain how you wind up at 2 ?
The right answer is 3 :D
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Explain how you wind up at 2 ?
The right answer is 3 :D
I looked at it mathematically.
Only way to get 3 lies and one truth is.
if you further look a it.
if we switch any of the answer, only one, it changes whole equation and initial condition.
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Ok, that's right. Its B.
Next one:
Suppose you are travelling in a train. There are only 4 other people in your berth. They are named 1, 2, 3 and 4 . Your wallet is stolen. Assume that the wallet was stolen by one of these 4 people and that only 3 of them lie.
Here are their statements: - 1: 2 stole the wallet. - 2: 3 didn't steal. - 3: I didn't steal. - 4: 3 stole your wallet.
Who actually stole your wallet?
I was incorrect first time. Condition is onky one speaks truth. Hadn't seen 3 s reply.
So both 2 and 3 say 3 didn't steal. Both can't say the truth. Hence both lie. Now 1 says 2 stole the wallet. If that is true, then both 2 and 3 are also speaking truth. Not possible.
So 1 2 and 3 are lying. 4 is telling the truth.
So 3 stole the wallet.
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I looked at it mathematically. Only way to get 3 lies and one truth is.
if you further look a it. if we switch any of the answer, only one, it changes whole equation and initial condition.
So I guess you're in agreement with me then ?
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I need to follow this thread ... bring it on guys!
I can ask couple of questions, let me know when shall I
