help

inzi_rocks · October 13, 2008, 8:10pm

okay i’m confuzzled.. here is the question

p(x) = 2x^3 + 5x^2 -23x + 10

So yeah I solved that and figured that x =2, x=0.5 and x=-5

NOW! It says ‘hence solve the equation: 2e^3x + 5e^2x + -23e^x + 10 = 0, givin ur answers in terms of natural logarithms’

Uhm yes… I need help urgently

Thanks.. and yeah Mods sorry i think it may be the wrong forum

Krypton · October 13, 2008, 8:11pm

Re: help

logarithms:rotfl:

cadet018 · October 13, 2008, 8:13pm

sorry… mein history mein thoda sa weak hoon

inzi_rocks · October 13, 2008, 8:14pm

Re: help

grrr its not funny its torture

I’m sleepy. and on Q6 only.. and I have a whole other hwk to do too, on natural logs and exponentials

abdelyuuki · October 13, 2008, 8:16pm

Re: help

ln everything, ln and e's will cancel

inzi_rocks · October 13, 2008, 8:18pm

Re: help

So I’ll get like… 2^3x etc etc… ?

Mirch · October 13, 2008, 8:19pm

abdelyuuki · October 13, 2008, 8:25pm

no, thats not how u cancel ln’s and e’s

inzi_rocks · October 13, 2008, 8:30pm

Re: help

then…

abdelyuuki · October 13, 2008, 8:39pm

Re: help

oh wait, ye tht is right, sorry :P didnt read it properly

cadet018 · October 13, 2008, 8:42pm

Re: help

.

inzi_rocks · October 13, 2008, 8:44pm

Re: help

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