Well the problem is related to DIFFERENTIATION-
Q-The diameter of a closed cylindrical tin is equal to the height of the tin.Show tht for a fixed volume,a tin made to this specification requires the least amount of sheet metal.
The last question related to differentiation then i move onto integration:(
Cooldude, r u trying 2 get us 2 do ur homework 4 u???
:nono:
moona acha tareeqa hai question ko ignore karnay ka loll…
wondering if u detest calculus to that extent …
Differentiate the volume of the tin with respect to the diamter and calculate the value at zero - the max or min value. Compute that this is the minimum value by doing the second differential and once you have shown that it is a minimum then compute the diamter in terms of the height.
Remeber height would be a constant when differentiating wrt to the diameter
Re: Calculus help required....
[QUOTE]
*Originally posted by The new COOLDUDE: *
Well the problem is related to DIFFERENTIATION-
Q-The diameter of a closed cylindrical tin is equal to the height of the tin.Show tht for a fixed volume,a tin made to this specification requires the least amount of sheet metal.
The last question related to differentiation then i move onto integration:(
[/QUOTE]
Seems you are doing Edexcel A levels Pure Mathematics syllabus... :)
This question is not easy as it sounds, caused quite a few problems since numerical values are not there.