Re: Let’s Play 1 2 3…
and 0 again:@:
Losty ![]()
Re: Let's Play 1 2 3...
again 0... zero... zero se pehle one it lead to 10.. than?
Re: Let's Play 1 2 3...
-27:@:
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after 10 there is 27... than.. 1027..
congrats finaly we reached 1027..
Re: Let's Play 1 2 3...
-33
Re: Let's Play 1 2 3...
thirteen one
thirteen two
thirteen three :@:
Re: Let's Play 1 2 3...
gaia yaar u not 33...
Re: Let's Play 1 2 3...
-78
Re: Let's Play 1 2 3...
its going all random.. no one to teach them.. i should take responsibility... ok bacho lets start from one 1 ...1 ...1
Re: Let's Play 1 2 3...
2....2....2.
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3...3..........3
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4 5 6 7 8 9 10:@:
Re: Let's Play 1 2 3...
10...11...12... baqi kal... now is study time...
Re: Let's Play 1 2 3...
Good good glad to see you are all learning lots of new numbers! Hehe! :)
Keep counting...1...2...3...and?
1
Re: Let's Play 1 2 3...
In the beam construction on the right, the four unknown reactions are *VA*, VB, VC and HA. The equilibrium equations are:**
Σ V = 0:
**VA − Fv + VB + VC = 0** Σ H = 0:
**HA − Fh = 0** Σ *MA* = 0:**
**Fv · a − VB · (a + b) - VC · (a + b + c) = 0.**
Re: Let's Play 1 2 3...
3397:)
Re: Let's Play 1 2 3...
**HA − Fh = 0** Σ *MA* = 0:**
Re: Let's Play 1 2 3...
''