Anyone can solve it?

[lethal_kamikaze]

Re: Anyone can solve it?

I hate math

[Pakiiza]

Re: Anyone can solve it?

@lethal_kamikaze

I hate math

me too
but I want to know, how it will be solved?

[lethal_kamikaze]

Re: Anyone can solve it?

Pehlay batao ke inaam kiya milay ga

[Pakiiza]

Re: Anyone can solve it?

@lethal_kamikaze

Pehlay batao ke inaam kiya milay ga

aisy hi inam mil jayga pehly silve karain, or waisy bhi mera ek inam banta tha par … bohat na insafi hay. me ko sab yaad hy mujhy mera inam milta to isy solve krny waly ko bhi inamm milta pr ab nahi

[lethal_kamikaze]

Re: Anyone can solve it?

Woh inaam oky i’ll let u knw. Ab solve karny pr kisko kiya mily ga yeh tello

[Pakiiza]

Re: Anyone can solve it?

Bohaaat sary Badaam with milk

[MM]

Re: Anyone can solve it?

@Pakiiza

Multiple choice question

If x=y2 and y=t2 then eliminate t

a) x2=y2
b) x2=y
c) x= y2
d) x2y2
e) xy2

This makes no sense…
If you’re eliminating for t, t is in only 1 of the two calculations.
So if you have y=t2, and since x is not mentioned in that calculation, then to eliminate for t, you would divide both sides by 2.
So… t=y/2

[Pakiiza]

Re: Anyone can solve it?

[Sanaabc]

Re: Anyone can solve it?

is it C?

[Sanaabc]

Re: Anyone can solve it?

@Miss Manno

This makes no sense…
If you’re eliminating for t, t is in only 1 of the two calculations.
So if you have y=t2, and since x is not mentioned in that calculation, then to eliminate for t, you would divide both sides by 2.
So… t=y/2

its t^2

[Ghost14]

Re: Anyone can solve it?

@Pakiiza

Multiple choice question

If x=y2 and y=t2 then eliminate t

a) x2=y2 b) x2=y c) x= y2 d) x2y2 e) xy2

1) Set both equal to y, and get x in terms of t.

Equation 1: x = y^2, take the square root of both sides -> y = SQRT(x)

Equation 2: y = t^2

Setting the two equal we get SQRT(x) = t^2

2) Solve for t by taking the square root of both sides, which gives us

FOURTHROOT(x) = t

3) Now sub the above expression into equation 2

y = [FOURTHROOT(x)]^2 (square of the fourth root is a square root)

y = SQRT(x)

Square both sides to get:

y^2 = x or x = y^2

So the answer is C

[khattichic]

Re: Anyone can solve it?

The answer is samosa chaat.

[queer]

Re: Anyone can solve it?

you are a patient man, ghost. but you didn't need to solve all that to get the final answer. it is where the question starts off. :D

[maria_d_great]

Re: Anyone can solve it?

:salam2:
bhaiyo aur behnoo iftar kr liya maine ab fir bhook lag pari soooooooooooooooo the answer is samosa chaat

[Ghost14]

Re: Anyone can solve it?

@queer

you are a patient man, ghost. but you didn’t need to solve all that to get the final answer. it is where the question starts off.

That’s what you get for procrastinating at 1 AM.

[Ghost14]

Re: Anyone can solve it?

@khattichic

The answer is samosa chaat.

But what if it goes straight to my hips?

[Southie]

Re: Anyone can solve it?

@Pakiiza

Multiple choice question

If x=y2 and y=t2 then eliminate t

a) x2=y2 b) x2=y c) x= y2 d) x2y2 e) xy2

C) x= y2

[Southie]

Re: Anyone can solve it?

@Ghost14

That’s what you get for procrastinating at 1 AM.

Our science teachers fav saying - procrastination is the thief of time

[Pakiiza]

Re: Anyone can solve it?

1) Set both equal to y, and get x in terms of t.

Equation 1: x = y^2, take the square root of both sides -> y = SQRT(x)

Equation 2: y = t^2

Setting the two equal we get SQRT(x) = t^2

2) Solve for t by taking the square root of both sides, which gives us

FOURTHROOT(x) = t

3) Now sub the above expression into equation 2

y = [FOURTHROOT(x)]^2 (square of the fourth root is a square root)

y = SQRT(x)

Square both sides to get:

y^2 = x or x = y^2

So the answer is C

Thank you sooo much Ghost14 :)

[Pakiiza]

Re: Anyone can solve it?

Thank you every one, Queer, CG,Southie,Sanaabc and special thanks to Ghost, Thank you all